Question

Equation Given: alt="h(t)=-4.9t^{2}+358" align="absmiddle" class="latex-formula">
Question: When is the penny at a height of 300 meters above the ground?

Answer 1

Answer:

At 3.44 seconds, the penny is at a height of 300 meters above the ground.

Step-by-step explanation:

Basically, we have to solve an equation here:

$-4.9t^{2} + 358 = 300$

Hence,

$-4.9t^{2} = 300 - 358$

$t^{2} = \frac{-58}{-4.9}$

$t = 3.44$

Hence, at 3.44 seconds, the penny is at a height of 300 meters above the ground.

Hope this helped!