Write nine hundred one and seventy-five thousands in expanded form

Here are graphs of two functions f and g the function h is defined by h(x)=f(x)-g(x)

bearhunter [10]

i did this last year lol ;-;

3 0

3 years ago

Solve the equation -7 = y for x.

Harlamova29_29 [7]

Answer:

x = 4y+28

Step-by-step explanation:

x/4 -7 = y

Solve for x

Add 7 to each side

x/4 -7+7 = y+7

x/4 = (y+7)

Multiply each side by 4

x/4*4 = 4(y+7)

x = 4y+28

5 0

3 years ago

Read 2 more answers

Can some one help me please

11111nata11111 [884]

Answer:

2x²√13

Step-by-step explanation:

Step 1: When there is multiplication under a square root sign (also called a radical sign), you can rewrite the expression as the product of two square roots, like this...

√(52x^4) can be rewritten as (√52)(√x^4)

Step 2: x^4 = x²x², so it's the same thing as saying (x²)², or "x-squared, squared". Taking the square root of it leaves just x-squared, so this simplifies to

(√52)x²

Step 3: When taking the square root of a number that is not a perfect square, you need to do a factor tree to see if you can break the number up into a product of perfect squares, or a perfect square multiplied by a prime number.

52 is an even number, so we an at least divide by 2.

52/2 is 26, so we have

(26)(2)

2 is a prime number, so we don't break that down any further.

26 is even so it is also divisible by 2,

26/2 is 13, so we have

(13)(2)(2)

which we can write as (13)(4) (groups pairs of numbers together)

(2)(2) is 4, which results in a perfect square, so we can rewrite √52 as

(√4)(√13), since √4 = 2, we simplify this expression to

2√13

So √(52x^4) breaks down to (√52)(√x^4), which further breaks down into

(2√13)(x²)

We simplify the expression to 2x²√13

3 0

3 years ago

Please Help!! I WILL MARK BRAINLIEST

victus00 [196]

Answer:

f-¹(x) = 2x – 8

f-¹(4) = 2(4) – 8 —> f-¹(4)= 8 - 8 =0

7 0

2 years ago

Can someone find r please

katrin2010 [14]

Answer:

$r = 3 \times \sqrt{2}$

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

$c = \sqrt{72}$