Write nine hundred one and seventy-five thousands in expanded form

The height, in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84. (

Schach [20]

Answer:

Step-by-step explanation:

Given that the height in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.

X is N(64, 2.8)

Or Z = $\frac{x-64}{2.8}$

a) the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.

$=P(59.8$

b) $P(X\geq 59)\\= P(X\geq -1.78)\\ \\=0.9625$

c) For 4 women to be height 260 inches is equivalent to

4x will be normal with mean (64*4) and std dev (2.8*4)

4x is N(266, 11.2)

$P(4x>260)= \\P(Z\geq -0.53571)\\=0.7054$

d) Z is N(0,1)

E(Z19) = $P(Z>19)\\= 0.000$

since normal distribution is maximum only between 3 std deviations form the mean on either side.

3 0

2 years ago

In the figure below, angle y and angle x form vertical angles. Angle y forms a straight line with the 60° angle and the 70° angl

Lynna [10]

The answer is 50 I believe

4 0

2 years ago

Picture attached. help please

Iteru [2.4K]

Answer:

A, D, F.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

N is a rational number.m is an irrational number.n2 cannot be an irrational number? why or why not

Korolek [52]

If n is rational, it means that

$n\in\mathbb{Q}\Rightarrow n=\frac{p}{q},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*$

Therefore when we do n² we can write it as

$n^2=\frac{p^2}{q^2},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*$

Remember that the product of two integer numbers is also an integer, therefore we can guarantee that

$p^2\in\mathbb{Z}\text{ and }q^2\in\mathbb{Z}^*$

Then we can confirm that n² is the quotient of two integers and the denominator is not zero, therefore, n² is always rational, it cannot be an irrational number

8 0

4 months ago

On a graph with y-values ranging from 108,175 to 986,432, what is a reasonable scale to use on a y-axis with 10 tick marks?

Black_prince [1.1K]

Increments of 100,000.
0 - 1,000,000
Essentially 0, 100,000, 200,000, 300,000, etc.

5 0

2 years ago