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elena55 [62]
3 years ago
15

Can anyone help me with this ?????

Mathematics
2 answers:
Sophie [7]3 years ago
4 0

Answer:

66.423 degrees

Step-by-step explanation:

The diagram is a right-angled triangle. It has two known sides and one known interior angle which is 90 degrees. The side opposite to the 90 degrees is called the Hypotenuse. it is also the longest side.

To find an angle, you need to know two sides. Per the angle at Y or angle XYZ, XY is adjacent. Using the adjacent XY and Hypotenuse YZ, we can write an expression using the trigonometric ratio called Cosine.

That's, Cos XYZ= 6/15

Angle XYZ=Cosine Inverse of 6/15

Angle XYZ=66.42. (2 dp)

ICE Princess25 [194]3 years ago
3 0

Answer:

66.4°

Step-by-step explanation:

cos XYZ = XY/ZY = 6/15 = 2/5 = 0.4

Using a calculator for cos^(-1) of 0.4 you get 66.42182152°

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Please don't take this down, it's just an innocent question
hichkok12 [17]

Answer:

False

Step-by-step explanation:

You can only get a two by rolling 2 ones

you can get a three by rolling a 1 and 2

They both only have 1 option to roll on too. So the answer is false, with 2 die the probibility will be the same.

4 0
3 years ago
Chords AB and CB intersect at E in circle O, as shown in the diagram below. Secant
Jobisdone [24]

Answer:

Step-by-step explanation:

4 0
2 years ago
Five guys walk into a bar, how many ways can they sit so as to be arranged from oldest to youngest?
Ipatiy [6.2K]

There are 24 ways in which 5 guys can sit if arranged from oldest to youngest.

We have,

Five guys.

Now,

We know that,

Total number of ways to arranged around a table (n) = (n-1)!

So,

For n = 5,

I.e.

(n - 1)! = (5 - 1)! = 4!

So,

Total number of ways to arranged Five guys rom oldest to youngest (n) = (n-1)!

i.e.

= (5 - 1)! = 4!

We get,

= 4 × 3 × 2 × 1

i.e.

Total number of ways to arranged Five guys rom oldest to youngest (n) = 24.

Hence we can say that there are 24 ways in which 5 guys can sit if arranged from oldest to youngest.

Learn more about arrangement here

brainly.com/question/15032503

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8 0
2 years ago
Calculate the average time the car took to reach each checkpoint. Record the average time in Table D of your Student Guide. The
zhuklara [117]

The average time the car took to reach each checkpoint are:

  • 2.07
  • 3.16
  • 4.11
  • 4.92

<h3>Average time</h3>

Given:

Time  interval

1              2      3           4

2.02    3.17   4.12    4.93

2.05    3.07  3.98   4.81

2.15    3.25  4.23    5.01

Hence:

First quarter checkpoint

Average time= (2.02 + 2.05 + 2.15) / 3

Average time=6.22/3

Average time= 2.07s

Second quarter checkpoint

Average time= (3.17 +3.07 + 3.25) / 3

Average time=9.49/3

Average time = 3.16 s

Third quarter check point

Average time= (4.12 + 3.98 + 4.23) / 3

Average time=12.33/3

Average time= 4.11 s

Fourth quarter check point

Average time = (4.93 + 4.81 + 5.01) / 3

Average time=14.75/3

Average time= 4.917 s

Average time=4.92s (Approximately)

Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.

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6 0
2 years ago
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
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