X = 60°
To work this out, you would do 50°+70° to get 120°. You would then subtract this from 180° (the total for any triangle) to get the final answer of 60°.
Answer:
Ax + Ay + 2A = 0 for any nonzero A, for example (A=1): x + y + 2 = 0
Step-by-step explanation:
The equation of a line is
Ax + By + C = 0
so we know that:
A*-3 + B*1 + C = 0
A*5 + B*-7 + C = 0
Let's subtract one from the other:
A*(-3 - 5) + B*(1 + -7) = 0
A*-8 + B*8 = 0
B*8 = A*8
B = A
Let's input B = A into the first two equations
A*-3 + A*1 + C = A*-2 + C = 0
A*5 + A*-7 + C = A*-2 + C = 0
checks out
C = 2A
So for any nonzero A the equation of
Ax + Ay + 2A = 0 produces a line passing between the points. Example would be
x + y + 2 = 0
Answer:
A. (2, -3).
Step-by-step explanation:
The first step is to complete the square on the terms in x and the terms in y:
x² - 4x +4 +y² +6y + 9 =4
= (x - 2)² - 4 + (y + 3)² - 9 + 4 + 9 = 4
= = (x - 2)² + (y + 3)² - 9 + 9 - 4 + 4 = 4
= (x - 2)² - (y + 3)² = 4.
So the centre is at (2, -3).
