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sdas [7]
3 years ago
7

a coast redwood tree is about 10 times as tall as an apple tree one of the tallest coast redwood even measured was 254 feet fall

how tall would you expect an apple tree to be ​
Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

25.4 feet tall

Step-by-step explanation:

254 divided by 10 equals 25.4

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A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t)
Viefleur [7K]

x(t) = 20t

y(t) = 40t - 5t^2

Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y

x(5) = 20(5) becomes x(5) = 100

y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y(5) = 75

The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75

Answer: 0.75

7 0
3 years ago
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Nadya [2.5K]

Answer:

D

Step-by-step explanation:

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3 years ago
What are the common denominator for 4/5and 1/3
Maru [420]

Answer:

15 is the answer hope this helps

7 0
2 years ago
Read 2 more answers
PLEASEE HELP!
melamori03 [73]

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

\left | b \right | = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

7 0
2 years ago
Please help, performance task: trigonometric identities
AnnZ [28]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

brainly.com/question/8120556

#SPJ1

4 0
1 year ago
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