Can yall pls help me

Mathematics

2 answers:

Leviafan [203]3 years ago

6 0

A. Learning and religion

seraphim [82]3 years ago

5 0

Learning and religion

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(-10,2) (-5,-1) find mid point

zmey [24]

The Mid - point of the line segment is at coordinates - M(- 7.5, 0.5)

We have two coordinate points - A(- 10, 2) and B(- 5, -1)

We have to find the midpoint of this line AB.

<h3>What is Mid - Point Theorem?</h3>

It states that a line with endpoint coordinates as - $(x_{1} ,y_{1} )$ and $(x_{2} ,y_{2} )$ has its mid - point at the coordinates -

$(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{(y_{1} +y_{2} )}{2} )$

According to question, we have -

First coordinate Point - $(x_{1} ,y_{1} )$ = (- 10, 2)

Second coordinate Point - $(x_{2} ,y_{2} )$ = (- 5, - 1)

Using the Mid - Point formula, we get -

$(x_{M} ,y_{M} ) =( \frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2} )$ =

$x_{M} = \frac{-10-5}{2} = \frac{-15}{2} = - 7.5\\\\y_{M} = \frac{2 - 1}{2} = \frac{1}{2} = 0.5$

Hence, the Mid - point of the line segment is at coordinates -

M(- 7.5, 0.5)

To solve more questions on Mid - points, visit the link below -

brainly.com/question/25377004

#SPJ1

5 0

1 year ago

Medal award ceremonies are held after each event. The following three flags are used to represent the gold, silver, and bronze m

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

Having the information on how many events there are and how many people in each event there would help me personally solve this

what i can tell you is its a probability thing a tree diagram is starting with something, like flipping a coin, and creating a branch for heads and tails, 0.5 for each branch. like the attachment I have on here. there's only 2 probable results from a coin, but if I have 5 events with 50 competitors I've created a lot more probable outcomes, it also depends on the events, if one of my competitors in 6'9" and ones 5'2" and the event is a dunk contest it would be slightly unfair and the probability of the person who is 5'2" changing your tree diagram :)