The day of the month that was 75% of the pond algae-free is: on day 28 or third day.
<h3>75% of the pond algae-free</h3>
Since we were told the algae doubled every day until it was covered in algae on day 30 of the month.
Hence:
Day 30 (First day)= It was 100% covered.
Day 29 (Second day)=It was 50% covered.
Day 28 (Third day )=it was 25% covered, which will be the same as 75% pond algae-free.
Therefore the day of the month that was 75% of the pond algae-free is: on day 28 or third day.
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The complete question is:
amount of algae covering the Smith's backyard pond doubled every day until it was completely covered in algae on day 30 of the month. On what day of that month was 75% of the pond algae-free?
Answer:
c = 10 feet
Step-by-step explanation:
Use the Pythagorean theorem: a^2 + b^2 = c^2
<u>Step 1: Plug in the information</u>
(6)^2 + (8)^2 = c^2
36 + 64 = c^2
100 = c^2
sqrt(100) = sqrt(c^2)
<em>10 = c</em>
<em />
Answer: c = 10 feet
The measure of angle A is 144.3 degrees and the angle to cut the molding is 54.3 degrees
<h3>How to solve for angle A?</h3>
Start by solving the acute part of angle A using the following sine function
sin(Ax) = (30 - 4)/32
Evaluate the quotient
sin(Ax) = 0.8125
Take the arc sin of both sides
Ax = 54.3
The measure of angle A is then calculated as:
A = 90 + Ax
This gives
A = 90 + 54.3
Evaluate
A = 144.3
Hence, the measure of angle A is 144.3 degrees
<h3>The angle to cut the molding</h3>
In (a), we have:
Ax = 54.3
This represents the angle where the molding would be cut
Hence, the angle to cut the molding is 54.3 degrees
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Answer:
.66
Step-by-step explanation:
Each side of the rhombus is 121 feet
