Question

1. Given f(x)=3x+8f(x)=3x+8 and g(x)=6x+6g(x)=6x+6 then what is (f+g)(−1))(f+g)(−1)) ?

Answer 1

f(x)=3x+8 and g(x)=6x+6 (f+g)(x) = f(x) + g(x) = (3x+8) + (6x+6) = 9x + 14 Then (f+g)(−1) = 9(-1) + 14 = 5 f(x)=6x+4 and g(x)=3x+7 (f+g)(x) = f(x) + g(x) = (6x+4) + (3x+7) = 9x + 11 Then (f−g)(1) = 9(1) + 11 = 20