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hram777 [196]
3 years ago
5

Find the area of the shape shown below.

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

26.75 units ^2

Step-by-step explanation:

Since the shape is complex, divide it into 3 right angled triangles and one square. Find the area of these individual shapes first, then fin the sum of these area to calculate the ultimate area of e complex shape:

Triangle 1 = 1/2 x 2 x 5 = 5 units ^2

Triangle 2 = 1/2 x 2 x 2 = 2 units ^2

Triangle 3 = 1/2 x 3.5 x 9 = 15.75 units ^2

Square = 2 x 2 = 4 units squared.

Now add all these up 15.75 + 2 + 5 + 4 = 26.75 units squared.

Hope this helps

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Correct. She could have also subtracted 100 from both sides, then divided by Negative one-half.

Step-by-step explanation:

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Answer:

Part A: Two pieces of information that are provided by the graph is the median which is 55 and the range which is 20-95. Two piece of information that is not provided by the graph is the mean and mode.

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3 years ago
Calculus= Integrate 5^x dx please break down how answer is 1/6x^6+C
aleksley [76]

Answer:

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

Step-by-step explanation:

Note that the integral of 5^x is not \frac{1}{6}x^6 + c

The solution is as follows:

Given

5^x

Required

Integrate

Represent the given expression using integral notation

\int\limits {5^x} \, dx

This question can't be solved directly;

We'll make use of exponential rules which states;

\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c

By comparing \int\limits {5^x} \, dx with \int\limits {a^x} \, dx;

we can substitute 5 for a;

Hence, the expression \int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c becomes

\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c

-------------------------------------------------------------------------------------

However, the integral of x^5 is \frac{1}{6}x^6 + c

This is shown below:

Given that x^5

Applying power rule;

Power rule states that

\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c

In this case (x^5), n = 5;

So, \int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c

becomes

\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c

\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c

\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c

4 0
3 years ago
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