<h2>
Answer:</h2>
The maximum volume of the box is:
1000 cm³
<h2>
Step-by-step explanation:</h2>
Let x be the length of the square base
and h be the height(h) of the box.
As we know that the length(l) and width(w) of the box is same( since the base is in the shape of square)
As we know that the surface area of box is given by:

We are given surface area of box=600 cm²
Hence,

The volume of box is given by:

Hence,

Now, for maxima or minima we have derivative equal to zero.

Now,

Now, as we know if for a given x

then that x is a point of maxima.
Hence, when we put x=10 we get: 
Hence, x=10 is a point of maxima
Also, the value of V at x=10 is:

Hence, the maximum volume of the box is:
1000 cm³