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Arlecino [84]
4 years ago
14

What is the correct method for moving a control file (assume you use PFILE)?

Computers and Technology
1 answer:
Mumz [18]4 years ago
4 0

Answer:

b

Explanation:

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FTP is commonly used to __________ and __________ files to a server.
Aleks [24]

Answer:

upload; download

Explanation:

FTP (File Transfer Protocol) is an internet protocol used to upload and download a file to a server, there are some programs help us to transfer this data to a server, in some cases, we're going to need these programs to upload website files to the server like images or videos, or some websites where do you need a user and passwords to upload file by FTP

8 0
4 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
What is the output of the following code snippet if the variable named cost contains 100? if cost &lt; 70 or cost &gt; 150 : dis
DanielleElmas [232]

Answer:

The output is: Your cost is  100

Explanation:

Given

The above code snippet

and

cost = 100

Required

Determine the output of the code

if cost < 70 or cost > 150

The above condition checks if cost is less than 70 or cost is greater than 150

This condition is false because 100 is neither less than 70 nor is it greater than 150

So, the else statement will be executed.

discount = cost

Which means

discount = 100

So, the print instruction will print: Your cost is  100

6 0
3 years ago
If one department chair—a professor—can chair only one department, and one department can have only one department chair. The en
vodka [1.7K]

Answer:

1:1

Explanation:

According to my research on different types of relationships between two variables, I can say that based on the information provided within the question the entities PROFESSOR and DEPARTMENT exhibit a 1:1 relationship. In other words there can only be one Professor per Department and vice-versa.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
In linux, a(n) ____ is a data structure that stores all information (such as file permissions, ownership, and file type) about a
Galina-37 [17]
Hi,


Answer => <span>Inode


Good Lessons </span>
4 0
4 years ago
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