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sertanlavr [38]
3 years ago
14

federal law requires public libraries to install filtering software on computers to prevent children from accessing adult conten

t online. This lawa. is expressly prohibited by the Constitution.b. does not substantially burden free speech.c. is subject to reasonable restrictions under the due process clause.d. is given strict scrutiny under the equal protection clause.
Computers and Technology
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

Option C, the law IS SUBJECT TO REASONABLE RESTRICTIONS UNDER THE DUE PROCESS CLAUSE.

Explanation:

The federal law which requires public libraries to install filtering software on computers was made to prevent children from accessing adult content.

The filtering software must block minors' access to images that are obscene, adult content or harmful to minors, as defined by law; and block adults' access to images that are obscene or adult content.

The acts place restrictions on the use of funding for Internet access that is available through the Library Services and Technology.

These restrictions take the form of requirements for Internet safety policies and technology that blocks or filters certain content from being accessed through the Internet.

Therefore, the option that best suits the question is, option C. The law is subject to reasonable restrictions under the due process clause.

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Create a 4x5 matrix with ones everywhere and zeros on the last row.
Stells [14]

Answer:

#include <iostream>

using namespace std;

int main() {

   int a[4][5];//declaring a matrix of 4 rows and 5 columns.

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       {

           if(i==3)//initializing last row as 0.

           {

               a[i][j]=0;

           }

           else//initializing last row as 1.

           {

               a[i][j]=1;

           }

       }

   }

   for(int i=0;i<4;i++)

   {

       for(int j=0;j<5;j++)

       cout<<a[i][j]<<" ";//printing the matrix.

       cout<<endl;

   }

return 0;

}

Output:-

1 1 1 1 1  

1 1 1 1 1  

1 1 1 1 1  

0 0 0 0 0

Explanation:

I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.

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allochka39001 [22]

Answer:

Explanation:

Using Python as our programming language

code:

def partitionArray(A,k):

flag=0

if not A and k == 1:

return "Yes"

if k > len(A) or len(A)%len(A):

return "No"

flag+=1

cnt = {i:A.count(i) for i in A}

if len(A)//k < max(cnt.values()):

return "No"

flag+=1

if(flag==0):

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k=int(input("k= "))

n=int(input("n= "))

print("A= ")

A=list(map(int,input().split()))[:n]

print(partitionArray(A,k))

Code Screenshot:-

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