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3 years ago

5

The slope of the line below is -1/7. Write a point-slope equation of the line using the coordinates of the labeled point ( 3, 3)

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1 answer:

Varvara68 [4.7K]3 years ago

8 0

Y - 3 = -1/7(x - 3)

answer is B.

hope it helps

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Katrina drinks 0.5 gallons of water per day which expression shows how to find the number of cups of water she drinks in a week

earnstyle [38]

Well we know that 1/2 a gallon (or 0.5 gallons) is equal to 8 cups. So one gallon is 16 cups. (keep this in the back of your mind)

Now to find how many cups she drinks in a day, find out how many gallons she drinks in a week.

So 0.5 (7) = 3.5

Now compute to see how many cups are in 3.5 gallons.

Answer: 56.0001

Understand?

7 0

3 years ago

Read 2 more answers

Select the correct answer.

antiseptic1488 [7]

Answer: Oc. 28

Step-by-step explanation:

5^2=25

3+5^2=3+25=28

4 0

2 years ago

An 18 tip is left on an $84 dinner bill. Write 2 different expressions that can be used to determine the total paid for dinner

motikmotik

Answer:

4.66666667

Step-by-step explanation:

8 0

3 years ago

Can someone help me with this, thanksssss

Effectus [21]

Answer:17

Step-by-step explanation:Follow pemdas.

Start with parentheses which is (5+2) which gives you 7.

Now next in Pemdas is Exponents. SO do 2 to power of 2 which is 4 .Then do 3 to the power of 3 which is 27.Next add 4 to 27 which is 31.so now do 7 times 2 is 14.Then take 31 and subtarct it from 14 which gives you 17.

Look at pic to see clearly how it was solved and the steps. I color code it to show the steps.

3 0

2 years ago

Read 2 more answers

Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

<u>Solution:</u>

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago