This data set represents the number of cups of coffee sold in a café between 8 a.m. and 10 a.m. every day for 14 days.

2 answers:

8 0

Put the numbers in order...
4,5,6,6,7,8,9,9,10,10,12,12,14,15

Q1 = (6 + 6) / 2 = 12/2 = 6
Q2 (median) = (9 + 9)/2 = 18/2 = 9
Q3 = (12 + 12) / 2 = 24/2 = 12

Q3 - Q1 = 12 - 6 = 6 (this is actually the interquartile range (IQR)

mestny [16]3 years ago

6 0

Here, just arrange the numbers in chronological order:
4, 5, 6, 6, 7, 8, 9, 9, 10, 10, 12, 12, 14, 15

Now, median = 9

1st quartile = [4, 5, 6, 6, 7, 8]
3rd quartile = [9, 9, 10, 10, 12, 12, 14, 15]

Q1 = 6+6/2 = 6
Q2 = 10+12 / 2 = 11

So, Q2 - Q1 = 11 - 6 = 5

In short, Your Answer would be 5

Hope this helps!

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A merry-go- round spins at a rate of 3 miles in 5 minutes.

Sidana [21]

36 miles an hour
3miles/5min to x/60min multiply top and bottom by 12 and you get 36miles/60min

4 0

2 years ago

In the 2004 Olympics, Adam won a gold medal in the men's 500 m kayak race, with a time of 1 min and 37.9 sec. He also won the br

Sedbober [7]

Answer:

The correct answer is Adam rowed faster in the men's 500-meter kayak race.

Step-by-step explanation:

To find the speed he rowed in both races, you need to divide the distance of the race by the time it took him to finish. In the first race, he rowed 500 meters and did it in a time of 1 minute 37.9 seconds, so the speed in that race would be $\frac{500}{97.9}$ or approximately 5.10725 meters per second. In the second race, Adam rowed a distance of 1000 meters and did it in a time of 3 minutes 28.2 seconds, which means his speed in that race would be $\frac{1000}{208.2}$ or approximately 4.80307 meters per second. Since his speed in the first race was faster than his speed in the second race, Adam rowed faster in the first race would be the correct answer.