Answer:
765
Step-by-step explanation:
To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
Se explanation
Step-by-step explanation:
The diagram shows the circle with center Q. In this circle, angle XAY is inscribed angle subtended on the arc XY. Angle XQY is the central angle subtended on the same arc XY.
The inscribed angle theorem states that an angle inscribed in a circle is half of the central angle that subtends the same arc on the circle. Therefore,

The measure of the intercepted arc XY is the measure of the central angle XQY and is equal to 144°.
All angles that have the same endpoints X and Y and vertex lying in the middle of the quadrilateral XAYQ have measures satisfying the condition

because angle XAY is the smallest possible angle subtended on the arc XY in the circle and angle XQY is the largest possible angle in the circle subtended on the arc XY.
Answer:
I believe it's asking for the additive inverse so,
1. 5
2. -28
3. 10.4
4. -0.875
5. 0
6. 8,003
Step-by-step explanation:
hope this is what u need
if it's right pls mark brainleist
The answer to this question is A