Question

The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I (d B) = 10 log left-bracket StartFraction I Over I Subscript 0 Baseline EndFraction Right-bracket, where I is the intensity of a given sound and I0 is the threshold of hearing intensity. What is the intensity, in decibels, [I(dB)], when I = 10 Superscript 32 Baseline (I Subscript 0)?

Answer 1

Answer:

The intensity in decibel is 320 decibel

Step-by-step explanation:

Given the intensity, or loudness, of a sound  measured in decibels (dB), according to the equation $I (dB)= 10log(\frac{I}{Io} )$ where;

I is the intensity of a given sound and

$Io$ is the threshold of hearing intensity

To get I(dB) when $I=10^{32} Io$

We will substitute the value of I = $I=10^{32} Io$ into the equation above to have;

$I (dB)= 10log(\frac{10^{32}Io }{Io} )\\I(dB)=10log10^{32}\\ I(dB)=32*10log10$

Since log10 = 1;

$I(dB)=32*10(1)\\I(dB)=320$

The intensity in decibel is 320 decibel

Answer 2

Answer:

correct answer is 737 or d on ( e d g e )

Step-by-step explanation:

cause