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Mrac [35]
3 years ago
9

Simplify 6 - 2³ + (-9 + 5) · 2.

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer: your answer is -10

Step-by-step explanation:j

if you dont believe me check your answer on a math website

Akimi4 [234]3 years ago
3 0

Answer:-10

Step-by-step explanation: solve by using pemdas and u get -10

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Un dispositivo de seguridad biométrico erróneamente rechaza la admisión de 1 en 1000 personas autorizadas de una instalación que
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Usando probabilidad condicional, se encuentra que hay una probabilidad de 0.0186 = 1.86% que la persona esta realmente autorizada para ingresar.

------------------

Probabilidad Condicional

P(B|A) = \frac{P(A \cap B)}{P(A)}

En que:

  • P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.  
  • P(A \cap B) es la probabilidad de que ocurran tanto A como B.  
  • P(A) es la probabilidad de que ocurra el evento A.

En este problema:

  • Evento A: Persona rechazada.
  • Evento B: Autorizada.

La probabilidad de una persona ser rechazada es:

  • \frac{1}{1000} = 0.001 de 95% = 0.95(autorizada).
  • \frac{1 000 000 - 1}{1 000 000} = 0.999999 de 5% = 0.05(non autorizadas).

O sea:

P(A) = 0.001(0.95) + 0.999999(0.05) = 0.05094995


La probabilidad de una persona estar autorizada y ser rechazada es:

P(A \cap B) = 0.001(0.95)

¿Cuál es la probabilidad que la persona esta realmente autorizada para ingresar?

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(B|A) = \frac{0.001(0.95)}{0.05094995}

P(B|A) = 0.0186

Probabilidad de 0.0186 = 1.86% que la persona esta realmente autorizada para ingresar.

Un problema similar es dado en brainly.com/question/18734831

3 0
3 years ago
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