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Norma-Jean [14]
3 years ago
8

If the customer's order came to $6.22 and he gave you $20.25 what is his change

Mathematics
2 answers:
taurus [48]3 years ago
7 0
He'll get $14.03 because 20.25 is what he gave but it only came up to 6.22 so 20.25-6.22=14.03
maxonik [38]3 years ago
3 0
$14.03, just subtract $6.22 from the $20.25

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A cake calls for 25 cups of sugar. If I use 225 cups of sugar, how many batches did I make?
Alja [10]

Answer:

9

Step-by-step explanation:

225/25= 9

9 batches

5 0
3 years ago
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gogolik [260]

Answer:

m

∠

N

=

67

∘

,

and

,

m

∠

P

=

113

∘

.

Explanation:

By what is given,  

m

∠

M

+

m

∠

N

=

90

∘

...

...

...

...

...

(

1

)

, and,

m

∠

N

+

m

∠

P

=

180

∘

...

...

...

...

...

...

...

...

.

(

2

)

Since,  

m

∠

M

=

23

∘

, by (1), we get,  

m

∠

N

=

90

∘

−

23

∘

=

67

∘

.

Using this in  

(

2

)

, we get,  

m

∠

P

=

180

∘

−

67

∘

=

113

∘

.

3 0
3 years ago
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sammy [17]

cool one

Step-by-step explanation:

4 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
What is 5/12 times 6 in multiply fractions with whole numbers
KiRa [710]
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4 years ago
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