Problema Solution
You have 800 feet of fencing and you want to make two fenced in enclosures by splitting one enclosure in half. What are the largest dimensions of this enclosure that you could build?
Answer provided by our tutors
Make a drawing and denote:
x = half of the length of the enclosure
2x = the length of the enclosure
y = the width of the enclosure
P = 800 ft the perimeter
The perimeter of the two enclosures can be expressed P = 4x + 2y thus
4x + 3y = 800
Solving for y:
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y = 800/3 - 4x/3
The area of the two enclosure is A = 2xy.
Substituting y = 800/3 - 4x/3 in A = 2xy we get
A = 2x(800/3 - 4x/3)
A =1600x/3 - 8x^2/3
We need to find the x for which the parabolic function A = (- 8/3)x^2 + (1600/3)x has maximum:
x max = -b/2a, a = (-8/3), b = 1600/3
x max = (-1600/3)/(2*(-8/3))
x max = 100 ft
y = 800/3 - 4*100/3
y = 133.33 ft
2x = 2*100
2x = 200 ft
The difference 96 -80 = 16 is a factor of both numbers, so is the greatest common factor.
96 + 80 = 16*(6 + 5)
Answer:
The answer is <ACD = 68°
Step-by-step explanation:
Using the property that the sum of interior angles in a triangle is equal 180°,we have:
<DAC + <ACD + <ADC = 180°
Finally, calculating the angle <ACD, we have:
<ACD = 180 - 4x
<ACD = 180 - 4 . 28
<ACD = 180 - 112
ACD = 68°
Answer:
The points P, Q, R and S all lie on the same line segment, in that order, such that the ratio of PQ : QR: RS is equal to 4:2:1.
Step-by-step explanation:
