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3 years ago

Rewrite the sum of 96+80 using the distributive property( as a multiple if a sum of two whole numbers with no common factor).

Mathematics

1 answer:

Georgia [21]3 years ago

6 0

The difference 96 -80 = 16 is a factor of both numbers, so is the greatest common factor.

96 + 80 = 16*(6 + 5)

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2n - 5 = 31<br><br> Answer: The value of n is ....

Romashka [77]

Answer:

n = 18

Step-by-step explanation:

2n - 5 = 31

Add 5 to each side

2n - 5+5 = 31+5

2n = 36

Divide each side by 2

2n/2 = 36/2

n = 18

7 0

3 years ago

Frank thinks he will need at about 12 1/2 kilograms of sand for sandbox he is building. The sand he wants is 3$ per kilogram. Ab

vesna_86 [32]

12 * 3 = 36, 1/2 * 3 = 1 1/2
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3 years ago

Henry had 2.5 lb of apples for a fruit salad. The recipe says that 5 lb of apples are needed for the salad. Henry went to the st

svetoff [14.1K]

<span> C. No, Henry did not get a reasonable amount of apples because he needed 2.5 more pounds of apples (2.5 + 2.5 = 5).

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3 years ago

Read 2 more answers

In hours Mariah can rake 3 backyards. how much of a backyard can she rake in 1hour?

Leviafan [203]

Answer: 3 or the whole backyard

Step-by-step explanation: In a hour she can rack 3 backyard. The question asked that how much of a backyard can she rake in 1 hour. She can rake the whole backyard in a hour.

7 0

3 years ago

Situation D: Suppose that, in a one-minute period during an electrical storm, the number of lightning strikes on a radar antenna

Crank

Answer:

21.77% probability that the antenna will be struck exactly once during this time period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 2.40$

Find the probability that the antenna will be struck exactly once during this time period.

This is P(X = 1).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-2.40}*2.40^{1}}{(1)!} = 0.2177$

21.77% probability that the antenna will be struck exactly once during this time period.

3 0

3 years ago