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3 years ago

5) Twelve divided by a number. 6) x +10 7) 3x-5 8) 6x + 2

Mathematics

1 answer:

Maru [420]3 years ago

7 0

Answer:

5)12/x

6) a number increased by 10

7) three times a number decreased by 5

8) 6 times a number increased by 2

Step-by-step explanation: "a number" refers to a variable.

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A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?

Tasya [4]

It should be 7.97 decigrams, since you want to convert 3 milligrams to decigrams (0.03), it is asking "How much more" which means you subtract. 8 subtracted from 0.03 is 7.97.

Hope this helps :)

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3 years ago

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What decimal is equivalent to StartFraction 8 over 100 EndFraction

makkiz [27]

Answer:

8/100 is equivalent to 0.08

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3 years ago

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Solve for x. Show your work with proper statements and notation.

9966 [12]

Answer:

x = 26

Step-by-step explanation:

The sum of the angles around point O = 360°, thus

x + 3x + 256 = 360 , that is

4x + 256 = 360 ( subtract 256 from both sides )

4x = 104 ( divide both sides by 4 )

x = 26

4 0

3 years ago

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

2 years ago

Rewrite the following expression x^9/7

Alexxx [7]

Answer:

$\sqrt[7]{x^9}$

Step-by-step explanation:

its kinda difficult for me to explain so i guess just use this equation next time:

$x^{m/n} = \sqrt[n]{x^m}$

4 0

2 years ago