You simply divide 32 ÷ 4 = 8, for problem A
Answer:
Step-by-step explanation:
56.4059 - 4.837 = 56 - 5 = 51
First you need the formula for SA of a cylinder: SA = 2(πr^2) + 2πr*h
(area of the top and bottom circles plus the side)
Then plug your values into the equation and rearrange to make h the subject:
1470.3 = 2π13^2 + 2π*13*h
26πh = 1470.3 - 338π
h = (1470.3 - 338π)/26π
=5.00042...
so h is approximately 5 units :)
Answer: a. 90°
Step-by-step explanation:
We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.
In the problem∠XYZ is the inscribed angle
∠XYZ=
⇒ ∠XYZ=
Since XZ is a diameter of the circle which is a line segment, thus ∠XZ=180°
∴ ∠XYZ=
∴ ∠XYZ=
Therefore, a. 90° is the measure of ∠XYZ.
A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.
Step-by-step explanation:
Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.
A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.
When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)