Please Help !!! Picture shown.
2 answers:
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Answer:
ΔJKL ≅ ΔMNO by SAS
Step-by-step explanation:
The question is incomplete, the question is as following:
ΔMNO is shown.
Which Δ below can be shown to be congruent to ΔMNO with only the given information?
Name the postulate that justifies your answer (SAS, AAS, HL, ASA or SSS).
Write the congruency statement for the triangles.
And see the attached figure which represent ΔMNO
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Check the given options to see which triangle from the option will be congruent to ΔMNO
1. In triangles MNO and ABC, there are two congruent sides and non-included angle - which mean (angle - side - side)
The (angle - side - side) Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent.
2. In triangles MNO and DEF, there are two congruent sides - there is not enough information
3. In triangles MNO and GHI, there are three congruent angles - which mean AAA (angle - angle - angle)
The AAA Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent. This postulate is used to prove the similarity between the triangles.
4. In triangles MNO and JKL, there are two congruent sides and included angle - SAS (side - angle - side)
MN ≅ JK , MO ≅ JL , ∠M ≅ ∠J
Answer:
Approximately 45% students signed up for neither canoeing or trekking.
Step-by-step explanation:
First we subtract the number of the students who signed up from the number of the total students to find the number of the students who did not signed up for either.
But there are 13 students who signed up canoeing and also for trekking.
Hence the number of students they signed up for activity is
72 + 23 - 13 = 82
And the number of students they not signed up for any activity is
150 - 82 = 68
so 68 students signed up neither for trekking nor canoeing. The percentage of those students are :
× 100 = 45.3333%
Approximately 45% students signed up for neither canoeing or trekking.
Answer:
Step-by-step explanation:
first you need to put the equation in y=mx+b form
y-3=(-1/2)(x+4)
y-3= (-1/2x)+4
y=-1/2x+1
then you just graph
the y intercept is 1 and the slope is -1/2 so it’s going to be a negative graph and it starts from 1 on the y axis
