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Marta_Voda [28]
3 years ago
10

Question 5

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:it’s either a or d

Step-by-step explanation:

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The mean temperature for the first 7 days in January was 6 °C.
IRISSAK [1]

Answer:

\frac{x + x + x + x + x + x + x}{7} = 6 \\  \frac{7x}{7}   = 6 \\ x = 6 \\  \frac{6 + 10}{8}  =  \frac{16}{2}

Step-by-step explanation:

answer =2

7 0
2 years ago
A shipping company charges 15 to ship a package and 5% of the shipping charge for insurance on the package what is the total cos
ddd [48]
The total cost of shipping a package with the cost of $15 exclusive if 5% insurance is 15.75 dollars. This is calculate by getting first the 5% of 15 dollars, 15 dollars multiplied by 5%, equal to 0.75 dollars. Then it will be added to the shipping cost of 15, which is equal to 15.75 dollars.
4 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
Someone please help!! ASAP
prohojiy [21]

Answer:

x=−5 and y=1

Step-by-step explanation:

7 0
3 years ago
3x-2x+4=2+x+2<br><br><br> Help I don’t get this. Shoot I’ll give you some points
andrew-mc [135]

Answer:

\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}

3x - 2x + 4 = 2 + x + 2 \\ x + 4 = 4 + x \\ x - x = 4 - 4 \\ 0 = 0

•°• LHS = RHS

✏ Hence, proved.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

\huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}

3 0
3 years ago
Read 2 more answers
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