Answer:
<h3>Solutions are x=2 and x=−2 . At these points the function has vertical asymptotes. To address the range, let's first transform...</h3>
First you put (x+5) into the initial function wherever you see x so it becomes
(x+5)^2+3(x+5)-10=x^2+kx+30
(x^2+5x+25)+(3x+15)-10 simplified left side
x^2+8x+30 fully simplified left side
thus k=8
x^2+8x+30=0 to find 0s
-4 + 3.7416573867739i
<span>-4 - 3.7416573867739i
</span>these are the roots you find after using the quadratic formula
the second one is the smallest
Answer:
substitute 8 into x =(8-2)2
(6)2=12
Answer:
I think the answer is 2. Hope this helps!