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Nadusha1986 [10]
3 years ago
15

Solve the system by elimination. 3x-10y=-25 4x+40y=20

Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
<span>3x-10y=-25</span>Add 10y10y to both sides
        3x=−25+10y

Regroup terms
<span><span>3x=10y-25<span>3x=10y−25</span></span>
Divide both sides by <span>3 <span>3
</span></span>x=10y-25/3

Factor out the common term <span>5 <span>5
your answer: x=5(2y-5)/3

</span></span><span>4x+40y=20
</span>Factor out the common term <span>4 <span>4
</span></span><span><span>4(x+10y)=20</span>
Divide both sides by <span>4<span>4
</span></span>x+10y<span>=20/4
</span>
<span>Simplify 20/4 to 5
</span><span><span>x+10y=5

</span>Subtract <span>10y<span>10y</span></span> from both sides
<span><span>your answer:  x=5-10y</span>
</span></span></span>
</span>
lana66690 [7]3 years ago
3 0
3x-10y=-25
4x+40y=20

12x-40y=-100
12x+120y=60

-160y=40

y=1/4
x=5/2


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