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3 years ago

How do I find the y intercept of a line?

Mathematics

1 answer:

Natalka [10]3 years ago

7 0

The y intercept is where the line crosses the y axis. Hope that helped

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Sandra knows the Pythagorean identity sin 2 ⁡ θ + cos 2 ⁡ θ = 1 . If she is told that 0 ≤ θ ≤ π 2 and cos ⁡ θ = 5 12, what will

slavikrds [6]

Answer:

$\text{tan}(\theta)=\frac{\sqrt{119}}{5}$

Step-by-step explanation:

We have been given that Sandra knows the Pythagorean identity $\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$ . She is told that $0\leq \theta\leq \frac{\pi}{2}$ and $\text{cos}(\theta)=\frac{5}{12}$ .

First of all, we will find value of sine theta using the given identity.

$\text{sin}^2(\theta)+\text{cos}^2(\theta)=1$

$\text{sin}^2(\theta)+(\frac{5}{12})^2=1$

$\text{sin}^2(\theta)+\frac{25}{144}=1$

$\text{sin}^2(\theta)+\frac{25}{144}-\frac{25}{144}=1-\frac{25}{144}$

$\text{sin}^2(\theta)=\frac{144-25}{144}$

$\text{sin}^2(\theta)=\frac{119}{144}$

$\text{sin}(\theta)=\sqrt{\frac{119}{144}}$

$\text{sin}(\theta)=\frac{\sqrt{119}}{12}$

$\text{tan}(\theta)=\frac{\text{sin}(\theta)}{\text{cos}(\theta)}$

$\text{tan}(\theta)=\frac{\frac{\sqrt{119}}{12}}{\frac{5}{12}}$

$\text{tan}(\theta)=\frac{\sqrt{119}*12}{5*12}=\frac{\sqrt{119}}{5}$

Therefore, $\text{tan}(\theta)=\frac{\sqrt{119}}{5}$ .

5 0

3 years ago

What is the area of a circular pizza with a radius of 9 cm?

kap26 [50]

Answer:

81π cm²

≈254.34 cm²

Step-by-step explanation:

The area formula for a circle is π×r².

Since the radius of the pizza is 9, we get:

π×9²=

2×π×81=

81π or ≈ 254.34 cm²

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3 years ago

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Find the derivative of f(x)=4x+7 at x = 5.

Roman55 [17]

Answer:

Step-by-step explanation:

f(x) is the same as y

if x=5 then you will multiply 5 by 4 which will give you 20

20 + 7 = 27

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2 years ago

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gladu [14]

It's D. a, b, and c refers to the coefficients of the numbers.

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3 years ago

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What figure is comprised of two rays that share a common end point called a vertex

Dvinal [7]

Angle is compromised of two rays that share a common endpoint called a vertex.

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