How can the key features of an exponential function be compared through tables and graphs?

Katie gives Maggie half of her pencils. Maggie keeps 5 pencils and gives the rest to Jamil. A. Write an expression for the numbe

Alexandra [31]

Here's what I mean when I write x/2 JUST IN CASE.

а.

Let the total number of pencils be x, then this implies that Maggie received x/2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means

that Jamil receives

x/2-5 pencils.

b. Expression of pencils given to Jamil is: x/2-5

Substitute x=16 in this expression: x/2-5

Simplify and evaluate: = 8-5= 3

Maggie gives 3 pencils to Jamil.

c. Expression of pencils given to Jamil is: x/2-5 to

Equate this expression with 1 to form an equation and solve for x all, the total

number of pencils if Jamil received 1 pencil:

x/2 - 5 = 1

Solve for x:

x = 2(1+ 5)

Evaluate:

x = 2(6) = 12

Katie had 12 pencils if Jamil received 1 pencil.

RESULT

a. Expression of number of pencils given to Jamil is x/2-5, where x is total number of pencils.

b. Maggie gives 3 pencils to Jamil.

c. Katie had 12 pencils if Jamil received 1 pencil.

5 0

3 years ago

Find the nth term of this quadratic sequence 4 9 16 25 36

TEA [102]

Answer:

Step-by-step explanation:

a₁ = 4 = 2² = (1 + 1)²

a₂ = 9 = 3² = (2 + 1)²

a₃ = 16 = 4² = (3 + 1)²

a₄ = 25 = 5² = (4 + 1)²

a₅ = 36 = 6² = (5 + 1)²

Therefore:

aₙ = (n + 1)² = n² + 2n + 1

3 0

3 years ago

Which is the ordered pair for the point on the x-axis

mariarad [96]

The ordered pair for the point on the x-axis that is on the line parallel to the given line and through the given point (-6, 10) is:

$\boxed{(6,0)}$

<h2>Explanation:</h2>

The complete question includes a graph. I have found it on the internet and has been attached below. So:

OUR GOAL:

To find an ordered pair for the point on the x-axis that is on the line parallel to the given line and through the given point (-6, 10)

With two points we can get the slope of a line, so for the given linewe have the following slope (m):

$P_{1}(-8,6) \\ \\ P_{2}(4,-4) \\ \\ \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m=\frac{-4-6}{4-(-8)} \\ \\ m=-\frac{10}{12}=-\frac{5}{6}$

Since the line we are looking for is parallel to the given line, then the slope of our unknown line (let's call it $m_{x}$ ) equals the slope of the given line. In other words:

$m_{x}=m=-\frac{5}{6}$

The point slope form of the equation of a line is:

$y-y_{0}=m(x-x_{0}) \\ \\ Where: \\ \\ P_{0}(x_{0},y_{0}) \ is \ a \ point \ on \ the \ line \\ \\ Here: \\ \\ P_{0}(-6,10) \\ \\ \\ Accordingly: \\ \\ y-10=-\frac{5}{6}(x-(-6)) \\ \\ y-10=-\frac{5}{6}(x+6)$

Finally, to find the ordered pair on the x-axis let's set $y=0$ then:

$y-10=-\frac{5}{6}(x+6) \\ \\ 0-10=-\frac{5}{6}(x+6) \\ \\ Isolating \ x: \\ \\ -\frac{5}{6}x-5=-10 \\ \\ \\ Add \ 5 \ to \ both \ sides: \\ \\ -\frac{5}{6}x-5+5=-10+5 \\ \\ -\frac{5}{6}x=-5 \\ \\ \\ Multiply \ by \ -\frac{6}{5} \ both \ sides: \\ \\ (-\frac{6}{5})(-\frac{5}{6}x)=(-5)(-\frac{6}{5}) \\ \\ \boxed{x=6}$