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raketka [301]
3 years ago
13

Sqaure root99, pi^2, 9.8 repeated decimal least to greatest

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

π^2, 9.8 repeating, square root of 99.

Step-by-step explanation:

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Answer:

2 = 64

1 = 90

3 = 10

Step-by-step explanation:

This is one possible example, remember that sides 2 and 3 must be less the 90 degrees if not it is not applicable

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It costs $3.75 for 5lbs of food for your puppy. How much is it for 1lb
alex41 [277]
75 cents is for 1lb


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3 years ago
The quotient of two numbers is negative. It must be true that _____.
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How to solve a circle of a radius of 12
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3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
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