Given:
Week 6 = 14 miles
Week 5 = 1.5 miles less than week 6.
1.5 miles is the common difference.
Week 6 = 14 miles
Week 5 = 12.5 miles
Week 4 = 11 miles
Week 3 = 9.5 miles
Week 2 = 8 miles
Week 1 = 6.5 miles
f(t) = first term + common difference(t-1)
f(t) = 6.5 miles + 1.5 miles (t-1)
f(1) = 6.5 + 1.5(1-1)
f(1) = 6.5 miles
f(2) = 6.5 + 1.5(2-1)
f(2) = 6.5 + 1.5
f(2) = 8 miles
Answer:
Total bikes and cars are 260
Step-by-step explanation:
<u>Cars</u>: 
<u>Bikes</u>: 
<u>Total</u>: 
Rounding to the nearest ten: 260
Once the numbers<span> have the same base and exponents, we can </span>add<span> or </span>subtract their<span> coefficients. </span><span> Determine the </span>number<span> by which to increase the smaller exponent by so it is equal to the bigger exponent.
I hope this helps!
</span>
The answer is 3km as there is 9 secs between it and distance = time/3 and 9/3 =3 so distance =3
Answer:
36
Step-by-step explanation:
