PLS HELP OF AREA ON TRIANGLE!!!

Mathematics

2 answers:

azamat3 years ago

3 0

Answer:

Area for Triangle is: 1/2bh or bh/2

Area for Trapezoid (As shown in picture):

1/2h(b1+b2)

You’d have to do 1/2 x 18(15+37) for the quesyion in the picture

Hope this helped!

Marat540 [252]3 years ago

3 0

Answer:

$area = (\frac{1}{2} (a + b) \times h) \\ \frac{1}{2} \times (15 + 37) \times 18ft \\ \frac{1}{2} \times 52ft \times 18ft \\ divide \: 52 \: by \: 2 \\ 26ft \times 18ft = 468 {ft}^{2} \\ answer = 468 {ft}^{2}$

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Who packed all the pies? Kane’s bakery makes four flavour pies. The weight of each flavour pie is follows:

svet-max [94.6K]

This is an identical problem answered by myself a few days ago. The answer is reproduced below for your convenience.

It is a very difficult problem if the box sizes are smaller or if there are more pies to pack.
For this particular problem, we first calculate the total weight of pies:
4 apple pies at 700 g = 2800 g
8 banoffee pies at 725 g =5800 g
3 custaard pies at 600 g = 1800 g
5 rhubarb pies at 675 g = 3375 g
for a total of 13775 g

The minimum number of boxes needed will be 13775/4000=3.44, or at least 4 boxes will be required.

We also note that 4 boxes will hold 16000 g, and we only need to pack 13775g, so there is a lot of margin.

We can proceed to do the mechanical way, fill in order of apple, banoffee, custard, and finally rhubarb pies.Following table shows how we fill, naively: box content Remaining to pack
Box A B C R Weight A B C R
0 4 8 3 5 (original order)
1 4 1 0 0 3525 0 7 3 5
2 0 5 0 0 3625 0 2 3 5
3 0 2 3 0 3250 0 0 0 5
4 0 0 0 5 3375 0 0 0 0
Total weight 13775 g

So that does the job, 4 boxes (minimum) with none exceeding 4000 g to pack a total of 13775 g of pies.

Brainly - brainly.com/sf/question/8898504

5 0

3 years ago

Zelda completed the right column of the table to help her find the difference of the fractions. 5/6 - 1/9

ArbitrLikvidat [17]

Answer:

13/18

Step-by-step explanation:

1. $\frac{5}{6} -\frac{1}{9}$