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borishaifa [10]
3 years ago
14

Use the discriminant and select whether the roots of 5x 2 - 4x + 3 = 0 are real or non-real.

Mathematics
2 answers:
malfutka [58]3 years ago
7 0
Get x=2/5 ,sothe answer are real 0nly one root
ohaa [14]3 years ago
5 0

Answer:  The roots of the given equation are non-real.

Step-by-step explanation:  We are given to use the discriminant and select whether the roots of the following quadratic equation are real or non-real :

5x^2-4x+3=0~~~~~~~~~~~~~~~~~~~~~~~`(i)

We know that

for the quadratic equation ax^2+bx+c,~a\neq 0, the discriminat is given by

D=b^2-4ac.

And, the roots will be

(i) real, if D is greater than or equal to zero,

(ii) non-real, if D < 0.

For the given equation (i), we have

a = 5,  b = -4   and   c = 3.

So, the discriminant is given by

D=b^2-4ac=(-4)^2-4\times5\times3=16-60=-44

Therefore, the roots of the given equation are non-real.

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We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
S=\frac{n(a_1+a_n)}{2}
first term is 1
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there are 100 terms so n=100

so the sum is S=\frac{100(1+100)}{2}
S=(50)(101)
S=5050
now you want us to divide by 10
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fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up




answer is 505
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