Answer:
2) Yes, each x-coordinate is only used once.
3) {1,2,3,4}
4) {25,45,60,70}
5) (3,60)
6) No because (4,7) and (4,25) share the same x-coordinate.
Step-by-step explanation:
A relation is a function if there is no more than one y-value assigned to an x.
Any x used can only be used once in an order pair.
You that here.
(1,25)
(2,45)
(3,60)
(4,70)
So basically because all of the x-coordinates are different, this is a function.
The domain is the x-coordinate of each pair (the first of each pair):
{1,2,3,4}.
The range is the y-coordinate of each pair (the second number of each pair):
{25,45,60,70}.
One ordered pair that I see in the table is (3,60). There are 3 others you can choose and I named them above.
{(4,10),(3,15),(1,5),(2,25),(4,25)} is not a function because there are more than one pairs with the same x-coordinate,4.
Answer:
2/21
Step-by-step explanation:
The question is badly formatted so cannot match the answer choice
Total number of tiles = 4 + 5 + 6 = 15
P(A) = P(drawing a black tile from 15 tiles) = 4/15
After event A, there are 14 tiles left : 3 black, + 5 white + 6 blue
P(B/A) = P(drawing white tile after a black tile has been drawn) = 5/14
P(A and B) = P(A).P(B/A) = 4/15 x 5/14 = 2/21
Note that P(B) = 5/15 since we are talking about independently drawing a white tile from the original stack of tiles
5.7 mile ride on the community bike ride
Answer:
The answer is 27
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
2(3y+6+3)=196−16
(2)(3y)+(2)(6)+(2)(3)=196+−16(Distribute)
6y+12+6=196+−16
(6y)+(12+6)=(196+−16)(Combine Like Terms)
6y+18=180
6y+18=180
Step 2: Subtract 18 from both sides.
6y+18−18=180−18
6y=162
Step 3: Divide both sides by 6.
6y
/6
=
162
/6
y=27
Answer:
The first set 4 , 6 , 6 , 8
The second set 2 , 6 , 6 , 10
Step-by-step explanation:
Mean is the average of the values in a set. This can be found by summing all the numbers and dividing by the total number. The median is the middle number when the values are listed in order of increasing size. The mode is the number(s) that appear the most often in the set.
The first set 4 , 6 , 6 , 8
mean = (4 + 6 + 6 + 8 )/4 = 6
median = (6+6)/2 = 6
Mode = 6
The second set 2 , 6 , 6 , 10
mean = (2 + 6 + 6 + 10)/4 = 6
median = (6+6)/2 = 6
Mode = 6
