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DIA [1.3K]
1 year ago
12

What is the image of (-8,-8)(−8,−8) after a dilation by a scale factor of \frac{1}{4} 4 1 ​ centered at the origin?

Mathematics
1 answer:
anastassius [24]1 year ago
3 0

We conclude that the image of (-8, -8), after a dilation by a scale factor of 1/4, is (-2, -2).

<h3>What is the image after the dilation?</h3>

For a point (x, y), a dilation by a scale factor of k gives the point (k*x, k*y).

Now, in this case, we have the point (-8, -8) and the scale factor is k = 1/4.

Then, using the above relation, we can write the coordinates of the image after the dilation as:

(-8*(1/4), -8*(1/4)) = (-2, -2).

We conclude that the image of (-8, -8), after a dilation by a scale factor of 1/4, is (-2, -2).

If you want to learn more about dilations, you can read:

brainly.com/question/3457976

#SPJ1

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Answer:

4x−7

Step-by-step explanation:

Being given our polynomial:

4x^{2}+ x - 14,

We must find the roots to get our answer.

x = (- 1 ± √(1 - 4*4*(-14)) / 8

x = (- 1 ± √225) / 8

x = ( -1 ± 15) / 8

x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4

x₂ = (- 1 - 15) / 8 = - 16/2 = - 8

The factors we came up with:

(x - x₁)(x - x₂)

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So,

The correct option is C.

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Answer:

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Let C1 represent circle 1

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If you analyze how much each number is increased, you will notice it alternates between adding 2, then adding 14:

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