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Wewaii [24]
3 years ago
9

A board of length 7 divided by the quantity x minus 2 end of quantity meters was cut into two pieces. If one piece is 3 divided

by the quantity x plus 2 end of quantity meters, express the length of the other board, in meters, as a rational expression.
Mathematics
1 answer:
bulgar [2K]3 years ago
4 0

Answer:

Length of other board =\frac{4x+20}{x^{2} -4} metres

Step-by-step explanation:

Given: Length of board = \frac{7}{x-2} metres

Length of board was divided into two.

Length of one piece = \frac{3}{x+2} metres

Let l = length of the other board

Length of the other board = Length of board - Length of one piece

So, l=\frac{7}{x-2}-\frac{3}{x+2}

l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}

Thus, length of the other board =\frac{4x+20}{x^{2} -4} metres

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The perimeter of a circle is 132 cm calculate its radius and area ​
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Answer:

r≈21.01cm

Step-by-step explanation:

I think that's the exact answer

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Let: f(x)=x+1 and g(x)=x^2-2 <br><br> find: f(x)•g(x)
lesya692 [45]

Answer: x3+x2−2x−2

Step-by-step explanation: Use the given functions to set up and simplify f ( x ) ⋅ ( g ( x ) ) .

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3 0
3 years ago
Please help due in 20 minutes!!
Nikitich [7]

Answer:

length is 15.5 and the width is 12.5

Step-by-step explanation:

Length rectangle = 3cm. longer than its width.

Rectangle perimeter = 56 cm.

find its dimensions?

P = 2L +2w

L= w + 3

P= 56

P = 2L +2w

56 = 2(w+3) +2(w)

56 = 2w +6 + 2w

4w= 56 - 6

4w = 50

w = 50/4

w = 12.5

L= 12.5 +3 = 15.5

L= 15.5

Solution:

Length= 15.5 cm

Width = 12.5 cm

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7 0
3 years ago
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What is the answer to that problem?
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8 0
3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
2 years ago
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