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Lina20 [59]
3 years ago
9

How to use the missing pieces strategy to compare two fractions. Include a diagram with explanation

Mathematics
1 answer:
hoa [83]3 years ago
8 0
First u get a fraction strip or make one then go to the denominator u count by how many the nomerator is then go to the other fraction and the same thing which ever is more is the greatest hope this helped.
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Whitepunk [10]
X is bigger than 65 but smaller or equal to 69. Looks a bit like this...6569.
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3 years ago
One day, a person went to a horse racing area. Instead of counting the number of humans an horses, he conuted 74 heads and 196 l
Komok [63]
A human has 1 head and 2 legs.
A horse has 1 head and 4 legs.

Let's make two equations from what we know.

There were a total of 74 heads.
There were a total of 196 legs.

Let's call humans 'x' and horses 'y'

The total number of heads were 74.
Humans have 1 head, and so do horses.

Our first equation is:
x + y = 74

There were a total of 196 legs. 
Humans have 2 legs, and horses have 4 legs.

Our second equation is:
2x + 4y = 196

Our two equations are:

x + y = 74
2x + 4y = 196

We need to solve this system of equations to find out how many humans and horses were at this racing event.

Multiply the first equation by 2.

2(x + y) = 2(74)
2x + 2y = 148

Our two equations are:

2x + 2y = 148
2x + 4y = 196

Subtract the first equation from the second equation.

2x - 2x + 2y - 4y = 148 - 196
2y - 4y = 148 - 196
-2y = - 48

Divide both sides by -2

y = 24

That means that there were 24 horses.

We can plug back in y = 24 into our first equation to find out how many humans there were.

x + y = 74
x + 24 = 74
x + 24 - 24 = 74 - 24
x = 50

There were 50 humans.

At the horse racing event, there were 24 horses and 50 humans.

Your final answer is B. 24 horses and 50 humans.

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Answer: x=2−2√3,2+2√3

Step-by-step explanation:

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