1. Initial value: 10
Rate of change: 3
Equation: y + 3
2. Initial value: 3
Rate of change: 3
Equation: y + 3
3. Initial value: 8
Rate of change: -2
Equation: y - 2
The initial value is the y-coordinate when x is equal to 0.
The rate of change is the difference between one point to the next immediate point.
The equation shows the rate of change.
the salesperson earns a fixed cost of $ 30 plus 2/9th of his sales
we have to find how many sales he gets to earn $ 100 for one day
so lets say that the number of sales for the day - x sales
and he earns 2/9th of his sales
therefore amount he earns for x sales is - 
this value plus his fixed earnings of $ 30 per day
so the amount he earns is 2x/9 + 30
this equals $ 100
so we can write the following equation
2x = 70 * 9
2x = 630
x = 315
so the amount of sales he earns for that day is 315 sales
Answer:
7/40
Step-by-step explanation:
La fraccion de Alemanes son 35/200=7/40
Answer:
66
Step-by-step explanation:
This was the formula that I used V=14h √(a+b+c)(b+c−a)(c+a−b)(a+b−c)
Hope this helps! :)
<span>The amount P as a function of t (in years) is given by
P(t) = P0 (1 + r/n)^(t n)
So if n = 4, and r = 0.02, and P0 = 1000, then
P(t) = 1000 (1 + 0.02/4)^(4 t) = 1000 (1 + 0.005)^(4 t)
At the end of the first quarter, t = 1/4, so
P(1/4) = $1000 (1.005)^(1) = $1005
At the end of the second quarter, t = 1/2 , therefore
P(1/2) = $1000 (1.005)^(2) = $1000 (1.010025) = $1010.03
At the end of the third quarter , t = 3/4, therefore
P(3/4) = $1000 (1.005)^(3) = $1000 (1.015075125) = $1015.08
At the end of the year, t = 4, therefore
P(1) = $1000 (1.005)^4 = $1000 (1.020150500625) = $1020.15
As for the second question, after the first period (quarter),
the formula becomes
P = P0 (1.005)^1 = 1.005 P0
which is choice A. </span>
