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horrorfan [7]
3 years ago
8

What is a prime factorization for 105

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0
The prime factorization of 105 is 3 x 5 x 7
Anestetic [448]3 years ago
5 0
  105
 21x5
7x3x5
So the prime factorization of 105 is 7x5x3
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A function of the form f(x) = mx + b, where m and b are real numbers, is called a _____
jasenka [17]

Answer:

A function of the form f(x) = mx + b, where 'm' and 'b' are real numbers, is called a <u>linear function.</u>

Step-by-step explanation:

A linear function is one in which the f(x) value of the function varies linearly with 'x'. When we plot a linear function on a graph, the resulting curve is always a straight line with the slope of the line being constant.

A linear function is of the form:

f(x)=mx+b, where, 'm' and 'b' are real numbers.

The degree or the highest exponent of 'x' in a linear function is always equal to 1.

Therefore, a function of the form f(x) = mx + b, where 'm' and 'b' are real numbers, is called a <u>linear function.</u>

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3 years ago
Directions: Name the coefficient (s) in the following expressions:
lozanna [386]

Answer:

Every number that's beside a letter. in 9s, 9 is the coefficient. that goes for every single problem you have.

3 0
3 years ago
Factor completely.<br> 150m^2nz+20mn^2c-120m^2nc-25mn^2z
Anika [276]

Answer:

The factor form is:

5mn\left(6m-n\right)\left(5z-4c\right)

Step-by-step explanation:

Here we have to find the factor of the expression:

150m^2nz+20mn^2c-120m^2nc-25mn^2z

So we need to take out the common terms, as we do for finding the greatest common factors.

Now the expression that is given can be re-written as:

150m^2nz+20mn^2c-120m^2nc-25mn^2z\\=150mmnz+20mnnc-120mmnc-25mnnz\\=30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz

Next, we will find the common terms, as follows;

30\cdot \:5nmmz+4\cdot \:5nmnc-24\cdot \:5nmmc-5\cdot \:5nmnz\\=5nm\left(30mz+4nc-24mc-5nz\right)\\

Now  we will factorise the expression:

\left(30mz+4nc-24mc-5nz\right)\\

as follows;

\left(30mz+4nc-24mc-5nz\right)\\=6m\left(5z-4c\right)+n\left(4c-5z\right)\\=\left(-4c+5z\right)\left(6m-n\right)\\

So the final factor form is:

150m^2nz+20mn^2c-120m^2nc-25mn^2z=5mn\left(6m-n\right)\left(5z-4c\right)

8 0
3 years ago
PLEASE HELP ASAP!!! 80 POINTS AND BRAINLIEST FOR BEST ANSWER!!! ONE MULTIPLE CHOICE QUESTION!!!
Andru [333]

Answer:

your answer should be c


8 0
3 years ago
Read 2 more answers
A study measured the speeds at which cars pass through a checkpoint. Assume the speeds are normally distributed such that the av
xxTIMURxx [149]

Answer:

0.3085 = 30.85% probability that the next car will be traveling less than 59 miles per hour.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 61, \sigma = 4

Calculate the probability that the next car will be traveling less than 59 miles per hour.

This is the pvalue of Z when X = 59. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59 - 61}{4}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085

0.3085 = 30.85% probability that the next car will be traveling less than 59 miles per hour.

7 0
3 years ago
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