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horrorfan [7]
3 years ago
8

What is a prime factorization for 105

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0
The prime factorization of 105 is 3 x 5 x 7
Anestetic [448]3 years ago
5 0
  105
 21x5
7x3x5
So the prime factorization of 105 is 7x5x3
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7/10 = 350/x<br><br> Please help cross multiply
Orlov [11]

Answer:

x=500

Step-by-step explanation:

7/10=350/x

cross-multiply by multiplying 350 to 10 and multiply 7 to x.

example:

7•x

350•10

7x=3500

divide both sides by 7

-------------

x=500

-------------

5 0
3 years ago
The value of [{(6to the power 2+8 to the power 2)to the power 1/2}]to the power 3​
Alex73 [517]

Answer:

Step-by-step explanation:

[(6^{2}+8^{2})^{\frac{1}{2}}]^{3} = [(36+64)^{\frac{1}{2}}]^{3}\\\\= [(100)^{\frac{1}{2}}]^{3}\\\\= 10^{3}\\\\= 1000

7 0
3 years ago
In △ABC, ∠ABC = 60○
Temka [501]

A given shape that is <u>bounded</u> by three sides and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of PB is <u>8.0</u> units.

A given <u>shape</u> that is <em>bounded</em> by three <em>sides</em> and has got three <em>internal angles</em> is referred to as a <em>triangle</em>. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The<em> sum</em> of the <u>internal</u> <u>angles</u> of any triangle is 180^{o}.

In the given question, point P is such that <APB = <APC = <BPC = 120^{o}. Also, line PB bisects <ABC into two <u>equal</u> measures. Thus;

<ABP = 30^{o}

Thus,

<ABP + <APB + <BAP = 180^{o}

30 + 120 + <BAP = 180^{o}

<BAP = 180^{o} - 150

<BAP = 30^{o}

Apply the <em>Sine rule</em> to determine the <u>value</u> of <em>PB</em>, such that;

\frac{AP}{Sin B} = \frac{BP}{Sin30}

\frac{8}{Sin30} = \frac{BP}{Sin 30}

BP = \frac{8*Sin30}{Sin 30}

     = \frac{4}{0.5}

BP = 8.0

Therefore, the <u>value</u> of <u>BP</u> = 8 units.

For more clarifications on applications of the Sine rule, visit: brainly.com/question/15018190

#SPJ1

8 0
2 years ago
The question is in the image below.
sineoko [7]

Answer:

The Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

a_n=a_1\cdot r^{n-1}

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

a_n=125\left(\frac{1}{5}\right)^{n-1}

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

  • a₁ = 125
  • r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

a_n=ra_{n-1}

Thus, substituting r = 1/5

\:a_n=\frac{1}{5}\left(a_{n-1}\right)  

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

3 0
3 years ago
Please help with this question
Dahasolnce [82]

Answer:

10X + 20 +5X +25 = 180

15x=180-45

X= 135/15

X=9

Please mark me brainliest and thank me and rate me. Sis.

8 0
3 years ago
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