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3 years ago

HAL SPENT 3/4 HOUR READING EACH DAY FOR 7 DAYS. HOW MUCH TOTAL TIME DID HE SPEND READING?

Mathematics

1 answer:

jasenka [17]3 years ago

4 0

It’s 315 hours because 60 divided by 4 equals 15 then multiply 15 and 3 equals 45 then multiply 45 and 7

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A = 3 and c = 12 c/a =

Bess [88]

Answer:

4, because 12/3 is 4 cause 3×4=12

3 0

3 years ago

9) Three times a number added to 12 gives -6. Find the number.

KatRina [158]

Answer:

The number is -6.

Step-by-step explanation:

Variable x = a number

Set up an equation:

3x + 12 = -6

Isolate variable x:

3x = -18

x = -6

Check your work:

3(-6) + 12 = -6

-18 + 12 = -6

-6 = -6

Correct!

7 0

3 years ago

Read 2 more answers

What is 6.685 rounded to the nearest hundredths place

loris [4]

Answer:

6.69

Step-by-step explanation:

The hundredths place is two decimal places to the right. This lands you at 8, so you must look at the number after it to determine whether you round up or down. So you look at 5, which rounds the 8 up to 9. Therefore, it is 6.69

7 0

3 years ago

Read 2 more answers

The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate

Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The margin of error is:

$MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

Given:

$\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90$

The critical value of <em>z</em> for 90% confidence level is:

$z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645$ *Use a standard normal table.

Compute the sample size required as follows:

$MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910$

Thus, the sample size required is 910.

5 0

3 years ago

HELP PLEASE!

zzz [600]

The answer is B djiekljfjroeo

4 0

3 years ago