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Tomtit [17]
3 years ago
14

What is the mode and range

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0
Mode: ( The number seem the most )

14. 240
15. 3 and 9
16. 60


Range: ( The biggest and smallest number subtracted )

14. 330-210=120
15. 11-3=8
16. 65-57=8
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Can someone help me please?
algol13

Answer:

x= 17

Step-by-step explanation:

6x+12=3x+63

Solve :)

7 0
3 years ago
The mean of six numbers is 25. Three of the numbers are 15, 15, and 30. The second unknown number is twice the first unknown num
svlad2 [7]

Answer:

The first unknown number is 10 the second is 20 and the third is 60

Step-by-step explanation

Since there is six numbers you have to multiply 25 times 6 = 150

Then 15+15+30=60

150-60= 90

10+20=30

30 times 2 equals 60

30+60=90

90+60= 150

150 divided by 6 = 25

4 0
3 years ago
Read 2 more answers
28 ft2 at $3.89 per square foot $71.98 $111.44 $108.92 $106.40
Alinara [238K]
The answer would be $108.92. You can solve this by multiplying @* by 3.89, getting 108.92.
4 0
3 years ago
How do i graph y=1/2Sinø/2?
podryga [215]
\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------

\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad   \right. \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}

\bf \bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

now, with that template in mind,

\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta   \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.


7 0
3 years ago
It takes Audrey 3/5 hour to paint 2/5 square yards of wood to be used for making shelves. How many square yards can she paint in
Pepsi [2]

Answer:

the answer is 2/3

Step-by-step explanation: i did the test!!

8 0
3 years ago
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