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earnstyle [38]
2 years ago
12

Doug checks census data for his city for a school project he's doing. He wants to show how many people live in the 5 areas of th

e city. What type of data is he collecting, and what kind of graph should he use to best display the results?
Categorical, stem-and-leaf
Numerical, bar graph
Categorical, circle graph
Numerical, histogram
Mathematics
2 answers:
Bond [772]2 years ago
5 0

Answer: Categorical, circle graph

Target:

How many people live in 5 area's of his city?

Explanation:

As he will display the people of 5 different areas in the city, that is categorical. Categorical and number of population can be represented very easily in a circle graph.

scoundrel [369]2 years ago
4 0

Answer:

i have no idea sorry but there are way tooooooooooo many words in this question so it doesnt really make much sence especially the bottom part if the question.

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use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

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3 0
2 years ago
A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equal
Rina8888 [55]

Step-by-step explanation:

Given that,

Sides of a triangle is  4 units, 6 units, and 7.21 units.

We need to find the area of a circle with a circumference that equals the perimeter of the triangle.

Perimeter of triangle = circumference of circle

4+6+7.21=2πr, r is the radius of circle

r = 2.73 units

Area of circle,

A=\pi r^2\\\\A=3.14\times (2.73)^2\\\\A=23.402\ \text{units}^2

or

A = 24 sq units

So, the area of the circle is 24 square units.

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(2x-10)/4 = 3x
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3 years ago
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Tems11 [23]
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Umnica [9.8K]

Answer:

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Step-by-step explanation:

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