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3 years ago

Where is a y axis on a bar graph?

Mathematics

2 answers:

Tpy6a [65]3 years ago

7 0

The y-axis runs vertically ( upand down))

Marta_Voda [28]3 years ago

3 0

The y axis is vertical on the bar graph the x axis is horizontal on the bar graph

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Marissa is painting her rectangular patio, with the exception of a bench that does not need to be painted:

mars1129 [50]

Answer:

A = (x + 15)(x + 10) − 5

Step-by-step explanation:

(x+15)(x+10)-5=A would be a solution

To make this easier, let's assign x a value. Let's say 3.

(3+15)(3+10)-5=A

(18)(13)-5=A

234-5=A

A=229

Now with this, we put x in the answer choice and the answer that gives an area of 229 is correct.

A. A=(3+20)(3+10)+12=(23)(13)+12=299+12=311 Answer A is wrong.

B. A=(3+20)(3+10)-12=(23)(13)-12=299-12=287 Answer B is wrong.

C. A=(3+26)(3+15)=(29)(18)=522 Answer C is wrong.

D. A=(3+14)(3+8)=(17)(11)=187 Answer D is wrong.

It's either I'm wrong or the answer choices are wrong.

New answer choices!

A. A=(3+20)(3+11)

=(23)(14)=322 Answer A is wrong.

B. A=(3+15)(3+10)+5

=(18)(13)+5=234+5=239 Answer B is wrong.

C. A=(3+15)(3+10)−5

=(18)(13)-5=234-5=229 Answer C is correct.

D. A=(3+9)(3+10)=(12)(13)=156 Answer D is wrong.

5 0

3 years ago

What is the GCF of 24 and 40

nikitadnepr [17]

Answer:

Step-by-step explanation:

24 = 2* 2 * 2 * 3

40 = 2 * 2 * 2 * 5

GCF = 2*2*2 = 8

6 0

2 years ago

Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o

myrzilka [38]

Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is $p = \frac{1}{5} = 0.2$

10 questions.

This means that $n = 10$

A) What is the probability that he will answer all questions correctly?

This is $P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024$

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

Since $P(X = 0) = 0.1074$ , from item b.

$P(X \geq 1) = 1 - 0.1074 = 0.8926$

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264$

$P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055$

$P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008$

$P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001$

$P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328$

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

8 0

3 years ago

Solve for X and y PLEASE GIVE FULL EXPLANATION HOW YOU GOT IT

Dennis_Churaev [7]

Answer:

(1, -1)

Step-by-step explanation:

we isolate y in the first equation

2x+y=1

-2x. -2x

y=1-2x

and now we fill y into second equation

4x-2(1-2x)=6

4x-2+4x=6

8x-2=6

+2 +2

8x=8

/8 /8

x=1

and now to find y we insert x

2(1)+y=1

2+y=1

-2. -2

y= -1

hopes this helps

4 0

11 months ago

May i please have some help

fomenos

Answer: Help with what

Step-by-step explanation:1 + 1 = 2

3 0

3 years ago