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White raven [17]
3 years ago
11

Where is a y axis on a bar graph?

Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0
The y-axis runs vertically ( upand down))
Marta_Voda [28]3 years ago
3 0
The y axis is vertical on the bar graph the x axis is horizontal on the bar graph
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Fatores 2m^4 - 18n^6
exis [7]
2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
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6 0
3 years ago
If m<ECD is six less than five times m<BCE. and m<BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

m∠BCE = 28° and m∠ECD = 134°

Step-by-step explanation:

* Lets explain how to solve the problem

- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD

- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

 of angle ECD

∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

  angle BCE

∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

3 0
3 years ago
Read 2 more answers
Select all that apply <br> thαnkѕ pєrѕσn
vodka [1.7K]
Im gonna guess and say the right ones might be
A = AB or A'B'
B = CB or C'B'
D =  CA or C'A'
Cus all equal the same side
H0P3 It H2LPS :)
or something
 
8 0
2 years ago
A 10.5-gallon aquarium is 2/3 full. How many more gallons of water does it take to fill the aquarium?
Natasha_Volkova [10]
The answer is 3.5 gallons
7 0
3 years ago
Read 2 more answers
Easy problem lots of points explain how to do it please
wlad13 [49]

Answer:

y= -2+\frac{2}{3}x

Step-by-step explanation:

Multiply both sides by 2

2x=3y+6

Move variable to the left-hand side and change its sing

-3y=6-2x

Divide both sides of the equation by -3

y= -2+\frac{2}{3}x

7 0
3 years ago
Read 2 more answers
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