All categories

4 years ago

One solution of x^2-64=0 is 8. what is the other solution?

2 answers:

8 0

Step 1: Add 64 to both sides.
x2−64+64=0+64
x2=64
Step 2: Take square root.
x=±√64
x=8 or x=−8
Answer:x=8 or x=−8

Hope this helps :D

ivann1987 [24]4 years ago

4 0

X² - 64 = 0
(x - 8)(x + 8) = 0

x = - 8, 8

Your other solution is - 8

You might be interested in

In a right triangle, Sin (4x + 10) º = Cos (6x) º. What is the value of x?

frez [133]

Answer:

Step-by-step explanation:

These angles will be equal when each of them measures 45 degrees. On the unit circle, 45 degrees and reference angles of 45 degrees are the only places where sin and cos are the same. This means that

sin(4x + 10) = 45 and cos(6x) = 45

If we add the angles together (the angles being 4x+10 and 6x) we get a 90 degree angle. Thus,

4x + 10 + 6x = 90 and

10x = 80 so

x = 8. Let's try it out:

sin(4(8) + 10) = sin(42) = .6691306064 and

cos(6(8)) = cos(48) = .6691306064

Yay!!!!!

6 0

3 years ago

Convert the following units. a. 108 eggs to dozens b. 35.79 dollars to cents c. 64 identical shoes to pairs d. 19,045 cents to d

kirill115 [55]

A. 9 dozens
b. 3,579 cents
c. 32 pairs
d. $190.45
e. 288 cookies

8 0

4 years ago

Read 2 more answers

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

TiliK225 [7]

Value of expression $(3xy/3x^2-12)*(x^2+3x+2/xy+y)$ is $\frac{x}{x-2}$ .

Step-by-step explanation:

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y) or ,

$(3xy/3x^2-12)*(x^2+3x+2/xy+y)$

Let's simplify this

⇒ $(\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})$

Factorizing the terms we get:

⇒ $(\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})$ { $a^2-b^2=(a+b)(a-b)$ }

⇒ $(\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})$

⇒ $(\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})$

Cancelling similar terms we get:

⇒ $\frac{x}{x-2}$

Therefore , Value of expression $(3xy/3x^2-12)*(x^2+3x+2/xy+y)$ is $\frac{x}{x-2}$ .

3 0

3 years ago

Help me please I added a picture to it

denis23 [38]

Answer:

probably

Step-by-step explanation:

- ----------------

3 0

3 years ago

Jessica calculated the missing side length of one of these triangles using the Pythagorean Theorem. Which triangle was it?

Alenkinab [10]

Answer:

Step-by-step explanation:

We can find a missing length of a triangle using a Pythagorean theorem if and only the triangle is a right angled triangle.

The side of the missing length is:

a^+b^=c^

2^+4^=c^

4+16=c^

20=c^

$\sqrt{20} = c ^{2} \\ 4 \sqrt{5} = c$

8 0

3 years ago