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vodomira [7]
3 years ago
9

On Sunday, Kayla spends $3.50 on cofee and buys two donuts, then on Monday she spends $1.25 on coffee and buys five donuts. How

much did one donut cost?​
Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

$1.08

Step-by-step explanation:

i think hope its right

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Simplify y - 3 over 3 +12
Hitman42 [59]

Answer:

y-3/15

Step-by-step explanation:

5 0
2 years ago
jennifer walks 8 miles in the same time she can jog 13 miles. if her jogging speed is 8mph faster than her walking speed, how fa
Elanso [62]

Answer:

12.8mph

Step-by-step explanation:

Let 'w' represent her walking speed

->if her jogging speed is 8mph faster than her walking speed

Jogging speed=  w+8

Using the time equation i.e time = dist/speed

For walking when distance is 8miles

time = dist / speed= 8/w hrs

For jogging when distance is 13miles

time = dist / speed= 13/(w+8) hrs

Equating the time

jog time = walk time

13/(w+8) = 8/w

By cross multiplying it

13w = 8w + 64

5w = 64

w=64/5

w=12.8mph

Therefore, 12.8mph is her walking speed.

5 0
2 years ago
I know it’s late but is anybody here
evablogger [386]

Answer:

b is 0

Step-by-step explanation:

yes, i am here :)

4 0
3 years ago
Read 2 more answers
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
lions [1.4K]
10, 10, 20 or either of u talking abt about tah the whole either 0-100
7 0
2 years ago
Find the number of 4 digit numbers that can be formed using the digits 1,2,3,4,5 if no digits is no repeated
loris [4]

Answer:

5 different numbers, 2 even

Step-by-step explanation:

Since we have 5 digits and they are non repeating we can use the permutation formula:

P(n, k) = \frac{n!}{k!}, $where $ k \leq n ; k, n \in \mathbb{N}

It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.

In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is: P(5, 4) = \frac{5!}{4!} = 5.

And out of those 5, only 2 are even

4 0
2 years ago
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