Answer: x= 207.8873386
Step-by-step explanation:
expecting both 2x-15 and 3x are angles in radiant, let's draw a rhombus ABCD
∠ABC = 2x-15
∠ BCD = 3x
∠ABC + < BCD= π ( 180° in radiant)
2x - 15 + 3x = π
5x - 15 = π
x - 3 = 1/5π
= 3.628318531 = 207.8873386
2x−15°+3x=180
5x-15°=180
5x=195°
x=39°
First term = T(1) is obtained by plugging n = 1 into the formula,
thus First term = 1^2 - 4 = 1 - 4
= 3 (answer)
Answer:
81 and 91
Step-by-step explanation:
Answer:
The probability that exactly one switch is good is
![P(x) =0.0392](https://tex.z-dn.net/?f=P%28x%29%20%3D0.0392)
Step-by-step explanation:
The probability that a switch is defective is:
![P(D) = \frac{2}{100} =0.02](https://tex.z-dn.net/?f=P%28D%29%20%3D%20%5Cfrac%7B2%7D%7B100%7D%20%3D0.02)
The probability that a switch is not defective is
![P(D') = 1-P(D)=0.98](https://tex.z-dn.net/?f=P%28D%27%29%20%3D%201-P%28D%29%3D0.98)
Therefore, if two switches are selected, the probability that exactly 1 is good is:
![P(1=1)=P (D) P (D ') + P (D') P (D)](https://tex.z-dn.net/?f=P%281%3D1%29%3DP%20%28D%29%20P%20%28D%20%27%29%20%2B%20P%20%28D%27%29%20P%20%28D%29)
![P(x)=(0.02)(0.98) + (0.98)(0.02)](https://tex.z-dn.net/?f=P%28x%29%3D%280.02%29%280.98%29%20%2B%20%280.98%29%280.02%29)
![P(x) =0.0392](https://tex.z-dn.net/?f=P%28x%29%20%3D0.0392)