Transpulmonary pressure, the difference between intrapulmonary and intrapleural pressures, prevents the lungs from collapsing
<span>A. Restriction enzymes would be used to cut the DNA into smaller pieces. The first step in DNA manipulation for genetic engineering is </span>to choose the piece of DNA from a source. Restriction enzymes are used in cutting these DNA pieces.
<span>This
type of symbiosis is commensalism. Commensalism is a relationship between two
organisms in which one benefits from the other and the other organism is not affected
in any way. From the question above, in the relationship, microscopic mites are
the commensals as they benefit from their host; humans and humans neither benefit
nor are harmed.</span>
Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
Answer:
0.5
Explanation:
Density=mass÷volume
So the density of the mineral is 3÷6 which equals 0.5