1.3*3=3.90
3.90*35=136.50
136.50 is all you need to provide at least three of the most expensive items.
You still have 13.50 left over
Step-by-step explanation:
Objective: Recall the properties.
a) 3+1=4
b) 3+7=7+3
c) 3+(7+4)=7+(3+4)
d). 3(7+4)=(3×7)+(3×4)
Answer:
d=1/2
b=1/25
b(row 2)=1/5
e=7/100
explanation: think about them as numbers out of 100 then simplify :)
Answer:
83 adult tickets and 217 student tickets.
Step-by-step explanation:
Let number of adult tickets sold = 
Given that total number of tickets = 300
So, number of student tickets = 300 - 
Cost of adult ticket = $15
Cost of student ticket = $11
Total collection from adult tickets = $
Total collection from student tickets = 
Given that overall collection = $3630

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.
Now , collection = $3632
Answer:
Riding 2 miles = $6.50
Riding m miles: C = 1.25m + 4
Step-by-step explanation:
(1.25)*(2) + 4 = $6.50