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faust18 [17]
3 years ago
6

A jar of sweet contains 5 yellow sweets, 4 red sweets, 8 green sweets, 4 orange sweets and 3 white sweets. Ola chose a sweet at

random, what is the possibility that she will pick either a yellow or orange sweet?
Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0

Answer:

9/24 or 37.5%

hope this helps :)

lana66690 [7]3 years ago
8 0

Hi,  

first thing you must do with a  probability problem is to count how many thing you have in your universe.

Here we are dealing with sweets. So let's count  :  5 +4+8+4+3 = 24  

and there is  5 yellow  so probability to pick up a yellow is  5/24

and there is 4 orange  so probabilitu to pick up a orange is  4/24

To say  :   Ola will pick orange or  yellow  mean  if she pick either one of the two sort is good.  So you add the proba of each :   5/24 +4/24 = 9/24

and then you must reduce if you can :   9/24 = 3*3 /8*3 =  3/8

So the probability that Ola pick a  yellow or orange sweet is  3/8 = 0.375

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Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!​
Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

\frac{3}{x + 4}  - \frac{1}{x + 3}  = \frac{x + 9}{(x^2 + 7x + 12)}

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

\frac{3*(x + 4)}{x + 4}  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

3  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x + 3)

3*(x + 3)  - \frac{(x + 4)*(x+3)}{x + 3}  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

3*(x + 3)  - (x + 4)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

(2*x + 5)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x^2 + 7*x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = (x + 9)*(x + 4)*(x+3)

Now we need to solve this:

we will get

2*x^3 + 19*x^2 + 59*x + 60 =  (x^2 + 13*x + 3)*(x + 3)

2*x^3 + 19*x^2 + 59*x + 60 =  x^3 + 16*x^2 + 42*x + 9

Then we get:

2*x^3 + 19*x^2 + 59*x + 60 - (  x^3 + 16*x^2 + 42*x + 9) = 0

x^3 + 3x^2 + 17*x + 51 = 0

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0
3 years ago
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Tpy6a [65]

Answer:

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Step-by-step explanation:

First, calculate the sales tax

Convert 8% into a decimal

8/100=0.08

Multiply the decimal by the cost of the game

60*0.08=4.8

$4.80 is just the tax, we have to find the total cost

Add the tax and the cost of the game

60+4.80=64.80

So, the total cost is $64.80

Hope this helps! :)

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