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PilotLPTM [1.2K]
3 years ago
15

Starting with a population of genetically identical mice, you discover two new independent mutant strains in which all of the an

imals have epileptic seizures. in both strains, you know that the epileptic seizures are due to a single dna mutation. you cross a mutant mouse from one strain to a mutant mouse from the second strain and find that none of their many offspring undergo spontaneous seizures. from this experiment you would conclude that the two mutant strains of mice most likely have mutations in:
Biology
1 answer:
Papessa [141]3 years ago
3 0
Had to look for the options and here is my answer. Based on the given experimentation above regarding some genetically identical mice, you would conclude that the two mutant strains of mice would most likely possess mutations in "<span>the same gene, but not necessarily the same DNA base position". Hope this answers your question.</span>
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Modify the existing vector's contents, by erasing the element at index 1 (initially 200), then inserting 100 and 102 in the show
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Answer:

Following are the code to this question:

#include <iostream>//defining header file

#include <vector>//defining header file

using namespace std;

void PrintVectors(vector<int> numsList)//defining a method PrintVectors that accept an array

{

   int j;//defining integer variable

   for (j = 0; j < numsList.size(); ++j)//defining for loop for print array value  

   {

       cout << numsList.at(j) << " ";//print array

   }

   cout << endl;

}

int main()//defining main method  

{

   vector<int> numsList;//defining array numsList

   numsList.push_back(101);//use push_back method to insert value in array

   numsList.push_back(200);//use push_back method to insert value in array

   numsList.push_back(103);//use push_back method to insert value in array

   numsList.erase(numsList.begin()+1);//use erase method to remove value from array

   numsList.insert(numsList.begin(), 100);//use insert method to add value in array

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   return 0;

}

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100 101 102 103  

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