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pickupchik [31]
3 years ago
14

Amy and Ebony are shopping. Amy has $77. Together, Amy and Ebony have less than $172. If x represents the amount of money Ebony

has, which of the following inequalities represents this information?
A.) $77 + x > $172
B.) $172 + x < $77
C.) $77 + x < $172
D.) x - $77 < $172
Mathematics
1 answer:
777dan777 [17]3 years ago
8 0
Amy = $77
Ebony = x

<span>Together, Amy and Ebony have less than $172:</span>
Amy + Ebony < $172

$77 + x < $172 (Answer C)

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Harlamova29_29 [7]

Answer:

Step-by-step explanation:

(x+3)² -5 =0 , use the formula (a+b) ² = a²+b²+2ab

x²+9 +6x -5 =0 , combine like terms

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x= (-6 ± √36-16) /2

x= (-6±√20)/2

x=(-6 +2√5)/2 and x=( -6-2√5) /2, factor 2 in the numerator and simplify

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4 0
3 years ago
I need help please.....
fgiga [73]

Answer:

C

Step-by-step explanation:

Move the decimal to the right 4 times

7 0
3 years ago
Solve for B. <br><br> R = x(A + B)<br><br> B = (R-A)/X<br> B = (A-Rx)/X<br> B = (R-Ax)/X
Ivanshal [37]
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4 0
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Fiesta28 [93]

Answer:

when many M&M candy are placed in a bag (say) and the Candy has different colors, when you decide to pick a candy out of the bag. you will get 0.20 Red candy in the bag out of the many candy with different colors.

Step-by-step explanation:

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3 0
3 years ago
What are the zeros of the polynomial function: f(x) = x3 – 5x2 -6x
shepuryov [24]

The zeros of the polynomial function: f(x) = x^3 – 5x^2 -6x is -1, 0, 6.

<u>Solution:</u>

Given, polynomial equation is x^{3}-5 x^{2}-6 x

We have to find the zeroes of the given polynomial.

So, let us equate it with 0.

\begin{array}{l}{\text { Then, } x^{3}-5 x^{2}-6 x=0} \\\\ {\rightarrow x\left(x^{2}-5 x-6\right)=0} \\\\ {\rightarrow x\left(x^{2}-(6-1) x-6\right)=0} \\\\ {\rightarrow x\left(x^{2}-6 x+x-6\right)=0} \\\\ {\rightarrow x(x(x-6)+1(x-6))=0} \\\\ {\rightarrow x(x-6)(x+1)=0} \\\\ {\rightarrow x=0 \text { or } x-6=0 \text { or } x+1=0} \\\\ {\rightarrow x=0 \text { or } 6 \text { or }-1}\end{array}

Hence, the roots of the given polynomial are -1, 0, 6.

6 0
3 years ago
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