If AB bisects 2 CAF, and angle EAF = 66°, then the angle BAF =

a football team gains 18 yards in one play and then loses 12 yards in the next what is the teams at total average

Papessa [141]

18 plus 12 divided by 2 = thats how u get the answer

5 0

3 years ago

Find the quadratic function y=f(x) whose graph has a vertex (−3,4) and passes through the point (−7,0). Write the function

olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola. The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front. So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex: x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

$a=-\frac{1}{4}$

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

$y=-\frac{1}{4}(x+3)^2+4$

Now we will FOIL out what's inside the parenthesis to get

$y=-\frac{1}{4}(x^2+6x+9)+4$

Simplify by distributing the -1/4 into the parenthesis:

$y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4$

Combine like terms to get

$y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}$

And there you go!

5 0

3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago

Let x be the first factor in an expression in scientific notation. Describe the possible values of x.

Igoryamba

What are some problems that can occur when using overrides? Check all that apply.

The style guide may become cluttered.Text with overrides can’t be exported to other documents.Word won’t allow you to use more than 10 styles in a document.<span>Text with the override won’t respond when changes are made to its original style.</span>

6 0

3 years ago

Pls help how do u do this???

viktelen [127]

Answer:

well well well

Step-by-step explanation:

free points

5 0

2 years ago