All categories

2 years ago

When can a kite also be called a square?

Mathematics

1 answer:

Papessa [141]2 years ago

4 0

When all sides are the same size

You might be interested in

I've been having struggles with math recently and would greatly appreciate help

BARSIC [14]

ANSWER:

$-4x^3+4x^2-4x+2$

STEP-BY-STEP EXPLANATION:

We have the following expression:

$(4x^3+6x^2-9x+1)-(8x^3+2x^2-5x-1)$

In order to operate, we must first break the parentheses and then group similar terms, like this:

$\begin{gathered} 4x^3+6x^2-9x+1-8x^3-2x^2+5x+1 \\ (4x^3-8x^3)+(6x^2-2x^2)+(-9x+5x)+(1+1) \\ \text{ therefore:} \\ -4x^3+4x^2-4x+2 \\ (4x^3+6x^2-9x+1)-(8x^3+2x^2-5x-1)=-4x^3+4x^2-4x+2 \end{gathered}$

6 0

1 year ago

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

3 years ago

Look at the picture for the question please show work.

lukranit [14]

$A=\dfrac{1}{2}ah\\
a=25 \text{ mm}\\
h=14 \text{ mm}\\\\
A=\dfrac{1}{2}\cdot25\cdot14\\
A=175 \text{ mm}^2 \Rightarrow C$

6 0

3 years ago

Help me please 2(x-4) = 6x - 6

Dmitrij [34]

Answer:

-1/2

Step-by-step explanation:

2(x-4)=6x-6

2x-8=6x-6

2x-6x-8=-6

-4x-8=-6

-4x=-6+8

-4x=2

x=2/-4

simplify

x=-1/2

8 0

2 years ago

Read 2 more answers

Please help. will give brainliest

vichka [17]

Answer:

B. The probability that the student received a grade better than C is 0.45

Step-by-step explanation:

<u>Total number of students:</u>

15 + 30 + 35 + 16 + 4 = 100

<h3>Statements</h3>

p(<D) = 4/100 = 0.04
0.04 ≠ 0.2
Incorrect

p(>C) = (30 + 15)/100 = 45/100 = 0.45
0.45 = 0.45
Correct

p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
0.55 ≠ 0.45
Incorrect

p(B or C) = (30 + 35)/100 = 65/100 = 0.65
0.65 ≠ 0.35
Incorrect

6 0

2 years ago