The probability of a chance event is 0.5, it is __________ to happen when compared to a chance event with a probability of 1.
2 answers:
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Answer:
Option (1) is the correct option.
Step-by-step explanation:
From the given frequency table,
Option (1).
Tossing an even number is more likely than tossing an odd number.
Frequencies of tossing even numbers 2, 4, 6 = 10, 10, 9
Frequencies of tossing odd numbers 1, 3, 5 = 8, 6, 7
Which shows frequencies of tossing even numbers are more.
Therefore, Option (1) is correct.
Option (2)
The number 2 will be the next number tossed.
Since it is unpredictable, therefore, this option is incorrect.
Option (3)
Number 4 is half as likely to be tossed as the number 3.
Frequency of tossing number 3 = 6
Frequency of tossing 4 = 10
Frequency of tossing 3 is not the half of tossing 4.
Therefore, Option (3) is incorrect.
Option (4)
Probability of tossing the number 2 =
=
=
=
Therefore, option (4) is incorrect.
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
Answer:
<h2>10</h2>Step-by-step explanation:
"12 more than the quiotent of a number n of and two decreased by 4"
Simplify:
Put n = 4 to the expresssion: